4(x-4)-(4x+4)=6(2x+2)

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Solution for 4(x-4)-(4x+4)=6(2x+2) equation: 



4(x-4)-(4x+4)=6(2x+2)

We move all terms to the left:

4(x-4)-(4x+4)-(6(2x+2))=0

We multiply parentheses

4x-(4x+4)-(6(2x+2))-16=0

We get rid of parentheses

4x-4x-(6(2x+2))-4-16=0



We calculate terms in parentheses: -(6(2x+2)), so:

6(2x+2)

We multiply parentheses

12x+12

Back to the equation:

-(12x+12)



We add all the numbers together, and all the variables

-(12x+12)-20=0

We get rid of parentheses

-12x-12-20=0

We add all the numbers together, and all the variables

-12x-32=0

We move all terms containing x to the left, all other terms to the right

-12x=32

x=32/-12

x=-2+2/3

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