4(x-4)-3(x+2)=-20

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Solution for 4(x-4)-3(x+2)=-20 equation: 



4(x-4)-3(x+2)=-20

We move all terms to the left:

4(x-4)-3(x+2)-(-20)=0

We add all the numbers together, and all the variables

4(x-4)-3(x+2)+20=0

We multiply parentheses

4x-3x-16-6+20=0

We add all the numbers together, and all the variables

x-2=0

We move all terms containing x to the left, all other terms to the right

x=2

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