4(x-4)-4=2(x+4)+x

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Solution for 4(x-4)-4=2(x+4)+x equation: 



4(x-4)-4=2(x+4)+x

We move all terms to the left:

4(x-4)-4-(2(x+4)+x)=0

We multiply parentheses

4x-(2(x+4)+x)-16-4=0



We calculate terms in parentheses: -(2(x+4)+x), so:

2(x+4)+x

We add all the numbers together, and all the variables

x+2(x+4)

We multiply parentheses

x+2x+8

We add all the numbers together, and all the variables

3x+8

Back to the equation:

-(3x+8)



We add all the numbers together, and all the variables

4x-(3x+8)-20=0

We get rid of parentheses

4x-3x-8-20=0

We add all the numbers together, and all the variables

x-28=0

We move all terms containing x to the left, all other terms to the right

x=28

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