4(x-4)-5=-3(-8x+6)-8x

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Solution for 4(x-4)-5=-3(-8x+6)-8x equation: 



4(x-4)-5=-3(-8x+6)-8x

We move all terms to the left:

4(x-4)-5-(-3(-8x+6)-8x)=0

We multiply parentheses

4x-(-3(-8x+6)-8x)-16-5=0



We calculate terms in parentheses: -(-3(-8x+6)-8x), so:

-3(-8x+6)-8x

We add all the numbers together, and all the variables

-8x-3(-8x+6)

We multiply parentheses

-8x+24x-18

We add all the numbers together, and all the variables

16x-18

Back to the equation:

-(16x-18)



We add all the numbers together, and all the variables

4x-(16x-18)-21=0

We get rid of parentheses

4x-16x+18-21=0

We add all the numbers together, and all the variables

-12x-3=0

We move all terms containing x to the left, all other terms to the right

-12x=3

x=3/-12

x=-1/4

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