4(x-4)/2=2(x+1)/6

Solution for 4(x-4)/2=2(x+1)/6 equation:

4(x-4)/2=2(x+1)/6

We move all terms to the left:

4(x-4)/2-(2(x+1)/6)=0

We calculate fractions


4x/()+(-(2(x+1)*2)/()=0


We calculate terms in parentheses: +(-(2(x+1)*2)/(), so:

-(2(x+1)*2)/(

We multiply all the terms by the denominator


-(2(x+1)*2)


We calculate terms in parentheses: -(2(x+1)*2), so:

2(x+1)*2

We multiply parentheses

4x+4

Back to the equation:

-(4x+4)


We get rid of parentheses

-4x-4

Back to the equation:

+(-4x-4)


We get rid of parentheses

4x/()-4x-4=0

We multiply all the terms by the denominator


4x-4x*()-4*()=0

We add all the numbers together, and all the variables

4x-4x*()=0