4(x-4)=-3(x-8)-x

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Solution for 4(x-4)=-3(x-8)-x equation: 



4(x-4)=-3(x-8)-x

We move all terms to the left:

4(x-4)-(-3(x-8)-x)=0

We multiply parentheses

4x-(-3(x-8)-x)-16=0



We calculate terms in parentheses: -(-3(x-8)-x), so:

-3(x-8)-x

We add all the numbers together, and all the variables

-1x-3(x-8)

We multiply parentheses

-1x-3x+24

We add all the numbers together, and all the variables

-4x+24

Back to the equation:

-(-4x+24)



We get rid of parentheses

4x+4x-24-16=0

We add all the numbers together, and all the variables

8x-40=0

We move all terms containing x to the left, all other terms to the right

8x=40

x=40/8

x=5

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