4(x-4)=19-7(4x+1)

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Solution for 4(x-4)=19-7(4x+1) equation:



4(x-4)=19-7(4x+1)
We move all terms to the left:
4(x-4)-(19-7(4x+1))=0
We multiply parentheses
4x-(19-7(4x+1))-16=0
We calculate terms in parentheses: -(19-7(4x+1)), so:
19-7(4x+1)
determiningTheFunctionDomain -7(4x+1)+19
We multiply parentheses
-28x-7+19
We add all the numbers together, and all the variables
-28x+12
Back to the equation:
-(-28x+12)
We get rid of parentheses
4x+28x-12-16=0
We add all the numbers together, and all the variables
32x-28=0
We move all terms containing x to the left, all other terms to the right
32x=28
x=28/32
x=7/8

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