4(x-4)=2(-8-x)+6x

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Solution for 4(x-4)=2(-8-x)+6x equation: 



4(x-4)=2(-8-x)+6x

We move all terms to the left:

4(x-4)-(2(-8-x)+6x)=0

We add all the numbers together, and all the variables

4(x-4)-(2(-1x-8)+6x)=0

We multiply parentheses

4x-(2(-1x-8)+6x)-16=0



We calculate terms in parentheses: -(2(-1x-8)+6x), so:

2(-1x-8)+6x

We add all the numbers together, and all the variables

6x+2(-1x-8)

We multiply parentheses

6x-2x-16

We add all the numbers together, and all the variables

4x-16

Back to the equation:

-(4x-16)



We get rid of parentheses

4x-4x+16-16=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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