4(x-4)=3(x+20)

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Solution for 4(x-4)=3(x+20) equation:



4(x-4)=3(x+20)
We move all terms to the left:
4(x-4)-(3(x+20))=0
We multiply parentheses
4x-(3(x+20))-16=0
We calculate terms in parentheses: -(3(x+20)), so:
3(x+20)
We multiply parentheses
3x+60
Back to the equation:
-(3x+60)
We get rid of parentheses
4x-3x-60-16=0
We add all the numbers together, and all the variables
x-76=0
We move all terms containing x to the left, all other terms to the right
x=76

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