4(x-4)=3(x+20)

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Solution for 4(x-4)=3(x+20) equation: 



4(x-4)=3(x+20)

We move all terms to the left:

4(x-4)-(3(x+20))=0

We multiply parentheses

4x-(3(x+20))-16=0



We calculate terms in parentheses: -(3(x+20)), so:

3(x+20)

We multiply parentheses

3x+60

Back to the equation:

-(3x+60)



We get rid of parentheses

4x-3x-60-16=0

We add all the numbers together, and all the variables

x-76=0

We move all terms containing x to the left, all other terms to the right

x=76

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