4(x-4)=3x+19

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Solution for 4(x-4)=3x+19 equation: 



4(x-4)=3x+19

We move all terms to the left:

4(x-4)-(3x+19)=0

We multiply parentheses

4x-(3x+19)-16=0

We get rid of parentheses

4x-3x-19-16=0

We add all the numbers together, and all the variables

x-35=0

We move all terms containing x to the left, all other terms to the right

x=35

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