4(x-4)=3x+19

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Solution for 4(x-4)=3x+19 equation:



4(x-4)=3x+19
We move all terms to the left:
4(x-4)-(3x+19)=0
We multiply parentheses
4x-(3x+19)-16=0
We get rid of parentheses
4x-3x-19-16=0
We add all the numbers together, and all the variables
x-35=0
We move all terms containing x to the left, all other terms to the right
x=35

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