4(x-4)=6(4x+12)

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Solution for 4(x-4)=6(4x+12) equation: 



4(x-4)=6(4x+12)

We move all terms to the left:

4(x-4)-(6(4x+12))=0

We multiply parentheses

4x-(6(4x+12))-16=0



We calculate terms in parentheses: -(6(4x+12)), so:

6(4x+12)

We multiply parentheses

24x+72

Back to the equation:

-(24x+72)



We get rid of parentheses

4x-24x-72-16=0

We add all the numbers together, and all the variables

-20x-88=0

We move all terms containing x to the left, all other terms to the right

-20x=88

x=88/-20

x=-4+2/5

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