4(x-4)=7(11+x)

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Solution for 4(x-4)=7(11+x) equation: 



4(x-4)=7(11+x)

We move all terms to the left:

4(x-4)-(7(11+x))=0

We add all the numbers together, and all the variables

4(x-4)-(7(x+11))=0

We multiply parentheses

4x-(7(x+11))-16=0



We calculate terms in parentheses: -(7(x+11)), so:

7(x+11)

We multiply parentheses

7x+77

Back to the equation:

-(7x+77)



We get rid of parentheses

4x-7x-77-16=0

We add all the numbers together, and all the variables

-3x-93=0

We move all terms containing x to the left, all other terms to the right

-3x=93

x=93/-3

x=-31

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