4(x-5)+13=7x-(3x+4)-3

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Solution for 4(x-5)+13=7x-(3x+4)-3 equation: 



4(x-5)+13=7x-(3x+4)-3

We move all terms to the left:

4(x-5)+13-(7x-(3x+4)-3)=0

We multiply parentheses

4x-(7x-(3x+4)-3)-20+13=0



We calculate terms in parentheses: -(7x-(3x+4)-3), so:

7x-(3x+4)-3

We get rid of parentheses

7x-3x-4-3

We add all the numbers together, and all the variables

4x-7

Back to the equation:

-(4x-7)



We add all the numbers together, and all the variables

4x-(4x-7)-7=0

We get rid of parentheses

4x-4x+7-7=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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