4(x-5)+3(7-2x)=2(5-3x)+1

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Solution for 4(x-5)+3(7-2x)=2(5-3x)+1 equation: 



4(x-5)+3(7-2x)=2(5-3x)+1

We move all terms to the left:

4(x-5)+3(7-2x)-(2(5-3x)+1)=0

We add all the numbers together, and all the variables

4(x-5)+3(-2x+7)-(2(-3x+5)+1)=0

We multiply parentheses

4x-6x-(2(-3x+5)+1)-20+21=0



We calculate terms in parentheses: -(2(-3x+5)+1), so:

2(-3x+5)+1

We multiply parentheses

-6x+10+1

We add all the numbers together, and all the variables

-6x+11

Back to the equation:

-(-6x+11)



We add all the numbers together, and all the variables

-2x-(-6x+11)+1=0

We get rid of parentheses

-2x+6x-11+1=0

We add all the numbers together, and all the variables

4x-10=0

We move all terms containing x to the left, all other terms to the right

4x=10

x=10/4

x=2+1/2

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