4(x-5)+3(x-2)=42

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Solution for 4(x-5)+3(x-2)=42 equation: 



4(x-5)+3(x-2)=42

We move all terms to the left:

4(x-5)+3(x-2)-(42)=0

We multiply parentheses

4x+3x-20-6-42=0

We add all the numbers together, and all the variables

7x-68=0

We move all terms containing x to the left, all other terms to the right

7x=68

x=68/7

x=9+5/7

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