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4(x-5)+3(x-5)=9(x-5)
We move all terms to the left:
4(x-5)+3(x-5)-(9(x-5))=0
We multiply parentheses
4x+3x-(9(x-5))-20-15=0
We calculate terms in parentheses: -(9(x-5)), so:We add all the numbers together, and all the variables
9(x-5)
We multiply parentheses
9x-45
Back to the equation:
-(9x-45)
7x-(9x-45)-35=0
We get rid of parentheses
7x-9x+45-35=0
We add all the numbers together, and all the variables
-2x+10=0
We move all terms containing x to the left, all other terms to the right
-2x=-10
x=-10/-2
x=+5
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