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4(x-5)+5=2(2x-3)-9
We move all terms to the left:
4(x-5)+5-(2(2x-3)-9)=0
We multiply parentheses
4x-(2(2x-3)-9)-20+5=0
We calculate terms in parentheses: -(2(2x-3)-9), so:We add all the numbers together, and all the variables
2(2x-3)-9
We multiply parentheses
4x-6-9
We add all the numbers together, and all the variables
4x-15
Back to the equation:
-(4x-15)
4x-(4x-15)-15=0
We get rid of parentheses
4x-4x+15-15=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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