4(x-5)+6=2(x+2)-12

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Solution for 4(x-5)+6=2(x+2)-12 equation: 



4(x-5)+6=2(x+2)-12

We move all terms to the left:

4(x-5)+6-(2(x+2)-12)=0

We multiply parentheses

4x-(2(x+2)-12)-20+6=0



We calculate terms in parentheses: -(2(x+2)-12), so:

2(x+2)-12

We multiply parentheses

2x+4-12

We add all the numbers together, and all the variables

2x-8

Back to the equation:

-(2x-8)



We add all the numbers together, and all the variables

4x-(2x-8)-14=0

We get rid of parentheses

4x-2x+8-14=0

We add all the numbers together, and all the variables

2x-6=0

We move all terms containing x to the left, all other terms to the right

2x=6

x=6/2

x=3

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