4(x-5)+6=2(x+3)-8

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Solution for 4(x-5)+6=2(x+3)-8 equation:



4(x-5)+6=2(x+3)-8
We move all terms to the left:
4(x-5)+6-(2(x+3)-8)=0
We multiply parentheses
4x-(2(x+3)-8)-20+6=0
We calculate terms in parentheses: -(2(x+3)-8), so:
2(x+3)-8
We multiply parentheses
2x+6-8
We add all the numbers together, and all the variables
2x-2
Back to the equation:
-(2x-2)
We add all the numbers together, and all the variables
4x-(2x-2)-14=0
We get rid of parentheses
4x-2x+2-14=0
We add all the numbers together, and all the variables
2x-12=0
We move all terms containing x to the left, all other terms to the right
2x=12
x=12/2
x=6

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