4(x-5)+7x=-3(x-2)

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Solution for 4(x-5)+7x=-3(x-2) equation: 



4(x-5)+7x=-3(x-2)

We move all terms to the left:

4(x-5)+7x-(-3(x-2))=0

We add all the numbers together, and all the variables

7x+4(x-5)-(-3(x-2))=0

We multiply parentheses

7x+4x-(-3(x-2))-20=0



We calculate terms in parentheses: -(-3(x-2)), so:

-3(x-2)

We multiply parentheses

-3x+6

Back to the equation:

-(-3x+6)



We add all the numbers together, and all the variables

11x-(-3x+6)-20=0

We get rid of parentheses

11x+3x-6-20=0

We add all the numbers together, and all the variables

14x-26=0

We move all terms containing x to the left, all other terms to the right

14x=26

x=26/14

x=1+6/7

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