4(x-5)+8(x-7)=3(x-5)+10x

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Solution for 4(x-5)+8(x-7)=3(x-5)+10x equation: 



4(x-5)+8(x-7)=3(x-5)+10x

We move all terms to the left:

4(x-5)+8(x-7)-(3(x-5)+10x)=0

We multiply parentheses

4x+8x-(3(x-5)+10x)-20-56=0



We calculate terms in parentheses: -(3(x-5)+10x), so:

3(x-5)+10x

We add all the numbers together, and all the variables

10x+3(x-5)

We multiply parentheses

10x+3x-15

We add all the numbers together, and all the variables

13x-15

Back to the equation:

-(13x-15)



We add all the numbers together, and all the variables

12x-(13x-15)-76=0

We get rid of parentheses

12x-13x+15-76=0

We add all the numbers together, and all the variables

-1x-61=0

We move all terms containing x to the left, all other terms to the right

-x=61

x=61/-1

x=-61

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