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4(x-5)+8=2(x-5)
We move all terms to the left:
4(x-5)+8-(2(x-5))=0
We multiply parentheses
4x-(2(x-5))-20+8=0
We calculate terms in parentheses: -(2(x-5)), so:We add all the numbers together, and all the variables
2(x-5)
We multiply parentheses
2x-10
Back to the equation:
-(2x-10)
4x-(2x-10)-12=0
We get rid of parentheses
4x-2x+10-12=0
We add all the numbers together, and all the variables
2x-2=0
We move all terms containing x to the left, all other terms to the right
2x=2
x=2/2
x=1
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