4(x-5)-3(x-4)+2=2(7-x)-(x-3)+1

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Solution for 4(x-5)-3(x-4)+2=2(7-x)-(x-3)+1 equation:


4(x-5)-3(x-4)+2=2(7-x)-(x-3)+1

We simplify the equation to the form, which is simple to understand
4(x-5)-3(x-4)+2=2(7-x)-(x-3)+1

Reorder the terms in parentheses
+(+4x-20)-3*(x-4)+2=2*(7-x)-(x-3)+1

Remove unnecessary parentheses
+4x-20-3+*(+x-4+)+2=+2+*(+7-x+)-(+x-3+)+1

Reorder the terms in parentheses
+4x-20+(-3x+12)+2=2*(7-x)-(x-3)+1

Remove unnecessary parentheses
+4x-20-3x+12+2=+2+*(+7-x+)-(+x-3+)+1

Reorder the terms in parentheses
+4x-20-3x+12+2=+(+14-2x)-(x-3)+1

Remove unnecessary parentheses
+4x-20-3x+12+2=+14-2x-(+x-3+)+1

Remove unnecessary parentheses
+4x-20-3x+12+2=+14-2x-1x+3+1

We move all terms containing x to the left and all other terms to the right.
+4x-3x+2x+1x=+14+3+1+20-12-2

We simplify left and right side of the equation.
+4x=+24

We divide both sides of the equation by 4 to get x.
x=6

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