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4(x-5)=(3x+1)
We move all terms to the left:
4(x-5)-((3x+1))=0
We multiply parentheses
4x-((3x+1))-20=0
We calculate terms in parentheses: -((3x+1)), so:We get rid of parentheses
(3x+1)
We get rid of parentheses
3x+1
Back to the equation:
-(3x+1)
4x-3x-1-20=0
We add all the numbers together, and all the variables
x-21=0
We move all terms containing x to the left, all other terms to the right
x=21
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