4(x-5)=-8(x+4)

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Solution for 4(x-5)=-8(x+4) equation: 



4(x-5)=-8(x+4)

We move all terms to the left:

4(x-5)-(-8(x+4))=0

We multiply parentheses

4x-(-8(x+4))-20=0



We calculate terms in parentheses: -(-8(x+4)), so:

-8(x+4)

We multiply parentheses

-8x-32

Back to the equation:

-(-8x-32)



We get rid of parentheses

4x+8x+32-20=0

We add all the numbers together, and all the variables

12x+12=0

We move all terms containing x to the left, all other terms to the right

12x=-12

x=-12/12

x=-1

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