4(x-5)=10-2(x+1)

Solution for 4(x-5)=10-2(x+1) equation:

4(x-5)=10-2(x+1)

We move all terms to the left:

4(x-5)-(10-2(x+1))=0

We multiply parentheses

4x-(10-2(x+1))-20=0


We calculate terms in parentheses: -(10-2(x+1)), so:

10-2(x+1)

determiningTheFunctionDomain
-2(x+1)+10

We multiply parentheses

-2x-2+10

We add all the numbers together, and all the variables

-2x+8

Back to the equation:

-(-2x+8)


We get rid of parentheses

4x+2x-8-20=0

We add all the numbers together, and all the variables

6x-28=0

We move all terms containing x to the left, all other terms to the right

6x=28

x=28/6

x=4+2/3