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4(x-5)=2(10-2x)
We move all terms to the left:
4(x-5)-(2(10-2x))=0
We add all the numbers together, and all the variables
4(x-5)-(2(-2x+10))=0
We multiply parentheses
4x-(2(-2x+10))-20=0
We calculate terms in parentheses: -(2(-2x+10)), so:We get rid of parentheses
2(-2x+10)
We multiply parentheses
-4x+20
Back to the equation:
-(-4x+20)
4x+4x-20-20=0
We add all the numbers together, and all the variables
8x-40=0
We move all terms containing x to the left, all other terms to the right
8x=40
x=40/8
x=5
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