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4(x-5)=2(3x+1)
We move all terms to the left:
4(x-5)-(2(3x+1))=0
We multiply parentheses
4x-(2(3x+1))-20=0
We calculate terms in parentheses: -(2(3x+1)), so:We get rid of parentheses
2(3x+1)
We multiply parentheses
6x+2
Back to the equation:
-(6x+2)
4x-6x-2-20=0
We add all the numbers together, and all the variables
-2x-22=0
We move all terms containing x to the left, all other terms to the right
-2x=22
x=22/-2
x=-11
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