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4(x-5)=3(x-7)+x+1
We move all terms to the left:
4(x-5)-(3(x-7)+x+1)=0
We multiply parentheses
4x-(3(x-7)+x+1)-20=0
We calculate terms in parentheses: -(3(x-7)+x+1), so:We get rid of parentheses
3(x-7)+x+1
We add all the numbers together, and all the variables
x+3(x-7)+1
We multiply parentheses
x+3x-21+1
We add all the numbers together, and all the variables
4x-20
Back to the equation:
-(4x-20)
4x-4x+20-20=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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