4(x-5)=x(x+3)

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Solution for 4(x-5)=x(x+3) equation: 



4(x-5)=x(x+3)

We move all terms to the left:

4(x-5)-(x(x+3))=0

We multiply parentheses

4x-(x(x+3))-20=0



We calculate terms in parentheses: -(x(x+3)), so:

x(x+3)

We multiply parentheses

x^2+3x

Back to the equation:

-(x^2+3x)



We get rid of parentheses

-x^2+4x-3x-20=0

We add all the numbers together, and all the variables

-1x^2+x-20=0

a = -1; b = 1; c = -20;
Δ = b2-4ac
Δ = 12-4·(-1)·(-20)
Δ = -79
Delta is less than zero, so there is no solution for the equation

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