4(x-5)=x+2(x-3)

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Solution for 4(x-5)=x+2(x-3) equation:



4(x-5)=x+2(x-3)
We move all terms to the left:
4(x-5)-(x+2(x-3))=0
We multiply parentheses
4x-(x+2(x-3))-20=0
We calculate terms in parentheses: -(x+2(x-3)), so:
x+2(x-3)
We multiply parentheses
x+2x-6
We add all the numbers together, and all the variables
3x-6
Back to the equation:
-(3x-6)
We get rid of parentheses
4x-3x+6-20=0
We add all the numbers together, and all the variables
x-14=0
We move all terms containing x to the left, all other terms to the right
x=14

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