4(x-5)=x+x+12

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Solution for 4(x-5)=x+x+12 equation: 



4(x-5)=x+x+12

We move all terms to the left:

4(x-5)-(x+x+12)=0

We add all the numbers together, and all the variables

4(x-5)-(2x+12)=0

We multiply parentheses

4x-(2x+12)-20=0

We get rid of parentheses

4x-2x-12-20=0

We add all the numbers together, and all the variables

2x-32=0

We move all terms containing x to the left, all other terms to the right

2x=32

x=32/2

x=16

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