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4(x-5x)=3(3-2x)
We move all terms to the left:
4(x-5x)-(3(3-2x))=0
We add all the numbers together, and all the variables
4(-4x)-(3(-2x+3))=0
We multiply parentheses
-16x-(3(-2x+3))=0
We calculate terms in parentheses: -(3(-2x+3)), so:We get rid of parentheses
3(-2x+3)
We multiply parentheses
-6x+9
Back to the equation:
-(-6x+9)
-16x+6x-9=0
We add all the numbers together, and all the variables
-10x-9=0
We move all terms containing x to the left, all other terms to the right
-10x=9
x=9/-10
x=-9/10
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