4(x-6)+2(x+4)=3(x+1)+3

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Solution for 4(x-6)+2(x+4)=3(x+1)+3 equation: 



4(x-6)+2(x+4)=3(x+1)+3

We move all terms to the left:

4(x-6)+2(x+4)-(3(x+1)+3)=0

We multiply parentheses

4x+2x-(3(x+1)+3)-24+8=0



We calculate terms in parentheses: -(3(x+1)+3), so:

3(x+1)+3

We multiply parentheses

3x+3+3

We add all the numbers together, and all the variables

3x+6

Back to the equation:

-(3x+6)



We add all the numbers together, and all the variables

6x-(3x+6)-16=0

We get rid of parentheses

6x-3x-6-16=0

We add all the numbers together, and all the variables

3x-22=0

We move all terms containing x to the left, all other terms to the right

3x=22

x=22/3

x=7+1/3

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