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4(x-7)+10=2(x-4)
We move all terms to the left:
4(x-7)+10-(2(x-4))=0
We multiply parentheses
4x-(2(x-4))-28+10=0
We calculate terms in parentheses: -(2(x-4)), so:We add all the numbers together, and all the variables
2(x-4)
We multiply parentheses
2x-8
Back to the equation:
-(2x-8)
4x-(2x-8)-18=0
We get rid of parentheses
4x-2x+8-18=0
We add all the numbers together, and all the variables
2x-10=0
We move all terms containing x to the left, all other terms to the right
2x=10
x=10/2
x=5
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