4(x-7)=0.3(x+2)+11

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Solution for 4(x-7)=0.3(x+2)+11 equation: 



4(x-7)=0.3(x+2)+11

We move all terms to the left:

4(x-7)-(0.3(x+2)+11)=0

We multiply parentheses

4x-(0.3(x+2)+11)-28=0



We calculate terms in parentheses: -(0.3(x+2)+11), so:

0.3(x+2)+11

We multiply parentheses

0.3x+0.6+11

We add all the numbers together, and all the variables

0.3x+11.6

Back to the equation:

-(0.3x+11.6)



We get rid of parentheses

4x-0.3x-11.6-28=0

We add all the numbers together, and all the variables

3.7x-39.6=0

We move all terms containing x to the left, all other terms to the right

3.7x=39.6

x=39.6/3.7

x=10+2.6/3.7

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