4(x-7)=2(10-x)+3

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Solution for 4(x-7)=2(10-x)+3 equation:



4(x-7)=2(10-x)+3
We move all terms to the left:
4(x-7)-(2(10-x)+3)=0
We add all the numbers together, and all the variables
4(x-7)-(2(-1x+10)+3)=0
We multiply parentheses
4x-(2(-1x+10)+3)-28=0
We calculate terms in parentheses: -(2(-1x+10)+3), so:
2(-1x+10)+3
We multiply parentheses
-2x+20+3
We add all the numbers together, and all the variables
-2x+23
Back to the equation:
-(-2x+23)
We get rid of parentheses
4x+2x-23-28=0
We add all the numbers together, and all the variables
6x-51=0
We move all terms containing x to the left, all other terms to the right
6x=51
x=51/6
x=8+1/2

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