4(x-9)+40=128

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Solution for 4(x-9)+40=128 equation: 



4(x-9)+40=128

We move all terms to the left:

4(x-9)+40-(128)=0

We add all the numbers together, and all the variables

4(x-9)-88=0

We multiply parentheses

4x-36-88=0

We add all the numbers together, and all the variables

4x-124=0

We move all terms containing x to the left, all other terms to the right

4x=124

x=124/4

x=31

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