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4(x-9)=4(+1/5x)
We move all terms to the left:
4(x-9)-(4(+1/5x))=0
Domain of the equation: 5x))!=0We multiply parentheses
x!=0/1
x!=0
x∈R
4x-(4(+1/5x))-36=0
We multiply all the terms by the denominator
4x*5x))-(4(-36*5x))+1=0
Wy multiply elements
20x^2-180x=0
a = 20; b = -180; c = 0;
Δ = b2-4ac
Δ = -1802-4·20·0
Δ = 32400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{32400}=180$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-180)-180}{2*20}=\frac{0}{40} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-180)+180}{2*20}=\frac{360}{40} =9 $
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