4(x2+0,5)=2

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Solution for 4(x2+0,5)=2 equation: 



4(x2+0.5)=2

We move all terms to the left:

4(x2+0.5)-(2)=0

We add all the numbers together, and all the variables

4(+x^2+0.5)-2=0

We multiply parentheses

4x^2+2-2=0

We add all the numbers together, and all the variables

4x^2=0

a = 4; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·4·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{8}=0$

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