4(x2-1)=2x+35

Solution for 4(x2-1)=2x+35 equation:

4(x2-1)=2x+35

We move all terms to the left:

4(x2-1)-(2x+35)=0

We add all the numbers together, and all the variables

4(+x^2-1)-(2x+35)=0

We multiply parentheses

4x^2-(2x+35)-4=0

We get rid of parentheses

4x^2-2x-35-4=0

We add all the numbers together, and all the variables

4x^2-2x-39=0

a = 4; b = -2; c = -39;
Δ = b2-4ac
Δ = -22-4·4·(-39)
Δ = 628
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{628}=\sqrt{4*157}=\sqrt{4}*\sqrt{157}=2\sqrt{157}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2\sqrt{157}}{2*4}=\frac{2-2\sqrt{157}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2\sqrt{157}}{2*4}=\frac{2+2\sqrt{157}}{8}
$