4(y)-2(4)-3(4)-3(y)+12=0

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Solution for 4(y)-2(4)-3(4)-3(y)+12=0 equation:


4(y)-2(4)-3(4)-3(y)+12=0

We simplify the equation to the form, which is simple to understand
4(y)-2(4)-3(4)-3(y)+12=0

Reorder the terms in parentheses
+(+4y)-2*(4)-3*(4)-3*(y)+12=0

Remove unnecessary parentheses
+4y-2+*(+4+)-3+*(+4+)-3+*(+y+)+12=0

Reorder the terms in parentheses
+4y+(-8)-3*(4)-3*(y)+12=0

Remove unnecessary parentheses
+4y-8-3+*(+4+)-3+*(+y+)+12=0

Reorder the terms in parentheses
+4y-8+(-12)-3*(y)+12=0

Remove unnecessary parentheses
+4y-8-12-3+*(+y+)+12=0

Reorder the terms in parentheses
+4y-8-12+(-3y)+12=0

Remove unnecessary parentheses
+4y-8-12-3y+12=0

We move all terms containing y to the left and all other terms to the right.
+4y-3y=0+8+12-12

We simplify left and right side of the equation.
+1y=+8

We divide both sides of the equation by 1 to get y.
y=8

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