4(y+1)+3y-1=6y+3

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Solution for 4(y+1)+3y-1=6y+3 equation: 



4(y+1)+3y-1=6y+3

We move all terms to the left:

4(y+1)+3y-1-(6y+3)=0

We add all the numbers together, and all the variables

3y+4(y+1)-(6y+3)-1=0

We multiply parentheses

3y+4y-(6y+3)+4-1=0

We get rid of parentheses

3y+4y-6y-3+4-1=0

We add all the numbers together, and all the variables

y=0

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