4(y+1)+3y-1=7y+3

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Solution for 4(y+1)+3y-1=7y+3 equation:


Simplifying
4(y + 1) + 3y + -1 = 7y + 3

Reorder the terms:
4(1 + y) + 3y + -1 = 7y + 3
(1 * 4 + y * 4) + 3y + -1 = 7y + 3
(4 + 4y) + 3y + -1 = 7y + 3

Reorder the terms:
4 + -1 + 4y + 3y = 7y + 3

Combine like terms: 4 + -1 = 3
3 + 4y + 3y = 7y + 3

Combine like terms: 4y + 3y = 7y
3 + 7y = 7y + 3

Reorder the terms:
3 + 7y = 3 + 7y

Add '-3' to each side of the equation.
3 + -3 + 7y = 3 + -3 + 7y

Combine like terms: 3 + -3 = 0
0 + 7y = 3 + -3 + 7y
7y = 3 + -3 + 7y

Combine like terms: 3 + -3 = 0
7y = 0 + 7y
7y = 7y

Add '-7y' to each side of the equation.
7y + -7y = 7y + -7y

Combine like terms: 7y + -7y = 0
0 = 7y + -7y

Combine like terms: 7y + -7y = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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