4(y+1)+5=6(y-1)+4

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Solution for 4(y+1)+5=6(y-1)+4 equation: 



4(y+1)+5=6(y-1)+4

We move all terms to the left:

4(y+1)+5-(6(y-1)+4)=0

We multiply parentheses

4y-(6(y-1)+4)+4+5=0



We calculate terms in parentheses: -(6(y-1)+4), so:

6(y-1)+4

We multiply parentheses

6y-6+4

We add all the numbers together, and all the variables

6y-2

Back to the equation:

-(6y-2)



We add all the numbers together, and all the variables

4y-(6y-2)+9=0

We get rid of parentheses

4y-6y+2+9=0

We add all the numbers together, and all the variables

-2y+11=0

We move all terms containing y to the left, all other terms to the right

-2y=-11

y=-11/-2

y=5+1/2

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