4(y+1)+y=5(y-1)+9

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Solution for 4(y+1)+y=5(y-1)+9 equation: 


Simplifying
4(y + 1) + y = 5(y + -1) + 9

Reorder the terms:
4(1 + y) + y = 5(y + -1) + 9
(1 * 4 + y * 4) + y = 5(y + -1) + 9
(4 + 4y) + y = 5(y + -1) + 9

Combine like terms: 4y + y = 5y
4 + 5y = 5(y + -1) + 9

Reorder the terms:
4 + 5y = 5(-1 + y) + 9
4 + 5y = (-1 * 5 + y * 5) + 9
4 + 5y = (-5 + 5y) + 9

Reorder the terms:
4 + 5y = -5 + 9 + 5y

Combine like terms: -5 + 9 = 4
4 + 5y = 4 + 5y

Add '-4' to each side of the equation.
4 + -4 + 5y = 4 + -4 + 5y

Combine like terms: 4 + -4 = 0
0 + 5y = 4 + -4 + 5y
5y = 4 + -4 + 5y

Combine like terms: 4 + -4 = 0
5y = 0 + 5y
5y = 5y

Add '-5y' to each side of the equation.
5y + -5y = 5y + -5y

Combine like terms: 5y + -5y = 0
0 = 5y + -5y

Combine like terms: 5y + -5y = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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