4(y+1)+y=5(y-1)=9

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Solution for 4(y+1)+y=5(y-1)=9 equation: 



4(y+1)+y=5(y-1)=9

We move all terms to the left:

4(y+1)+y-(5(y-1))=0

We add all the numbers together, and all the variables

y+4(y+1)-(5(y-1))=0

We multiply parentheses

y+4y-(5(y-1))+4=0



We calculate terms in parentheses: -(5(y-1)), so:

5(y-1)

We multiply parentheses

5y-5

Back to the equation:

-(5y-5)



We add all the numbers together, and all the variables

5y-(5y-5)+4=0

We get rid of parentheses

5y-5y+5+4=0

We add all the numbers together, and all the variables

9!=0

There is no solution for this equation

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