4(y+1)+y=8(y-1)+6

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Solution for 4(y+1)+y=8(y-1)+6 equation: 


Simplifying
4(y + 1) + y = 8(y + -1) + 6

Reorder the terms:
4(1 + y) + y = 8(y + -1) + 6
(1 * 4 + y * 4) + y = 8(y + -1) + 6
(4 + 4y) + y = 8(y + -1) + 6

Combine like terms: 4y + y = 5y
4 + 5y = 8(y + -1) + 6

Reorder the terms:
4 + 5y = 8(-1 + y) + 6
4 + 5y = (-1 * 8 + y * 8) + 6
4 + 5y = (-8 + 8y) + 6

Reorder the terms:
4 + 5y = -8 + 6 + 8y

Combine like terms: -8 + 6 = -2
4 + 5y = -2 + 8y

Solving
4 + 5y = -2 + 8y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-8y' to each side of the equation.
4 + 5y + -8y = -2 + 8y + -8y

Combine like terms: 5y + -8y = -3y
4 + -3y = -2 + 8y + -8y

Combine like terms: 8y + -8y = 0
4 + -3y = -2 + 0
4 + -3y = -2

Add '-4' to each side of the equation.
4 + -4 + -3y = -2 + -4

Combine like terms: 4 + -4 = 0
0 + -3y = -2 + -4
-3y = -2 + -4

Combine like terms: -2 + -4 = -6
-3y = -6

Divide each side by '-3'.
y = 2

Simplifying
y = 2

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