4(y+1)+y=8(y-1)+7

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Solution for 4(y+1)+y=8(y-1)+7 equation: 



4(y+1)+y=8(y-1)+7

We move all terms to the left:

4(y+1)+y-(8(y-1)+7)=0

We add all the numbers together, and all the variables

y+4(y+1)-(8(y-1)+7)=0

We multiply parentheses

y+4y-(8(y-1)+7)+4=0



We calculate terms in parentheses: -(8(y-1)+7), so:

8(y-1)+7

We multiply parentheses

8y-8+7

We add all the numbers together, and all the variables

8y-1

Back to the equation:

-(8y-1)



We add all the numbers together, and all the variables

5y-(8y-1)+4=0

We get rid of parentheses

5y-8y+1+4=0

We add all the numbers together, and all the variables

-3y+5=0

We move all terms containing y to the left, all other terms to the right

-3y=-5

y=-5/-3

y=1+2/3

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