4(y+1)+y=8(y-1)6

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Solution for 4(y+1)+y=8(y-1)6 equation: 



4(y+1)+y=8(y-1)6

We move all terms to the left:

4(y+1)+y-(8(y-1)6)=0

We add all the numbers together, and all the variables

y+4(y+1)-(8(y-1)6)=0

We multiply parentheses

y+4y-(8(y-1)6)+4=0



We calculate terms in parentheses: -(8(y-1)6), so:

8(y-1)6

We multiply parentheses

48y-48

Back to the equation:

-(48y-48)



We add all the numbers together, and all the variables

5y-(48y-48)+4=0

We get rid of parentheses

5y-48y+48+4=0

We add all the numbers together, and all the variables

-43y+52=0

We move all terms containing y to the left, all other terms to the right

-43y=-52

y=-52/-43

y=1+9/43

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